Question

in a given figure ABC is an isosceles triangle with ab is equal to AC and P is a point on side AC through a line is drawn to intersect b p produced in Q such that angle A B Q is equal to angle A C Q prove that angle A is equal to 90 + half angle A​

Answer 1

Answer:

angle ABC =angle ACB...............Equation1

suppose angle QBC=1

ABP=2

ACB=3    and

ACQ=4

given   2=4

From equation1        angle ABC=3

but angle ABC=2+1

but 2=4

thus angle ABC=4+1

thus 3=4+1

By angle sum property,angle BAC+(1+2)+(4+1)=180

by proving the equation we get angle A=90+half angle A

Step-by-step explanation: