In a given figure, ABCD is a parallelogram in which LBAO= 35* and LCOD= 65*. Find a)LABO b) LODC
(L represents angle sign ok?)
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So we get ∠ AOB = ∠ COD = 105o Consider △ AOB By sum property of a triangle ∠ OAB + ∠ AOB + ∠ ABO = 180o By substituting the values in above equation 35o + 105o + ∠ ABO = 180o On further calculation ∠ ABO = 180o – 35o – 105o By subtraction ∠ ABO = 180o – 140o ∠ ABO = 40oRead more on Sarthaks.com - https://www.sarthaks.com/725732/in-the-adjoining-figure-abcd-parallelogram-in-which-bao-35-dao-40and-cod-105-calculate
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