Question

in a given figure abcd is a quadrilateral in which the bisectors of angle b and c meet in the point o if angle a is 130 and d is 100 find the angle cod​

Answer 1

$soulution \: -$

$we \: have$

$abcd \: is \: a \: quadrilateral \\ given \: data$

$angle \: = 130 \\ angle \: = 100$

$so$

$angle \: b + angle \: c + angle \: a + angle \: d = 360$

$(b + c) = 360 - (a + d)$

$(b + c) = 360 - (130 + 100)$

$(b + c) = 360 - 230$

$(b + c) = 130$

$according \: to \: given \: question \:$

$angle \: ocb = \frac{angle \: b}{2}$

$angle \: ocb = \frac{angle \: c}{2}$

$now \:$

$angle \: ocb \: + angle \: obc = \frac{angle \: b + angle \: c}{2} = 230$

$angle \: cob + 230 = 180$

$angle \: cob = 180 - 230$

$angle \: cob = 50$