Math, asked by sharansingh482004, 5 months ago

in a given figure ABCD is a square if AC= 20√2cm the area of triangle ABC is

Answers

Answered by payalvaidya
0

explanation:

ABCD is a square .

sides of square are equal

AB = BC = CD = DA = 20√2

area of triangle ABC = 1/2 × base × hight

= 1/2 × BC × AB

= 1/2 × 20√2 × 20√2

= 1/2 × 20×20×√2×√2

= 1/2 × 400 × 2

= 800 / 2

= 400 sqcm

area of triangle ABC is 400 sqcm

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