Question

in a given figure if angle DBC is 70 degree and angle BAC is equal to 40 degree then find the value of angle BCD

Answer 1

Heya.......

Your answer's in pic........

Thanks....!!!

XD

Sorry baby 'wink'

Answer 2

$\red{Solution} \:$

→ABCD is a parallelogram

Therefore,

Angle A = Angle C = 70°

In ∆ BCD

Angle DBC + Angle C + Angle CDB =180° ( Angle Sum property of ∆)

→ Angle CDB = 180-70-80

→ Angle CDB = 30°

Now,

When, AB II BC And BC is the transversal

Therefore,

Angle ADB = Angle BDC

→Angle ADB = 80°