Question

In a given figure if ∆AOC = (2x-10) and ∆BOC =(3x+20).Find the value of x.And also find the value ∆AOC and∆BOC​

Answer 1

Answer:

2x-10+3x+20=180

5x+10=180

5x=170

x=34

2x-10=2*34-10=58°

3x+20=3*34+20=102+20=122°