in a given figure PA and PB are two tangents to a circle with Centre O from an external point P such that P A = 5 and angle APB = 60 degree find the length of the chord AB
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Answer:
∠ APO = 30° (half of ∠APB)
∠AOP = 90°
Sin 30 = AO/AP
1/2 = AO/5
AO = 5/2
AO = BO
⇒ AB = 5/2 + 5/2
= 5
Step-by-step explanation:
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