In a given fraction if the numerator is multiplied by 2 and the denominator is reduced by 5 we get 6/5but the numerator of the given fraction is inc. by 8 and the denominator is doubled we get 2/5 find the fraction
Answers
AnswEr:-
Determined fraction = 12/25
1st case:-
- Numerator × 2 & Denominator -5 =fraction : 6/5
Let the numerator be N & denominator be D.
ATQ:-
➠ 2N/D - 5 = 6/5
➠ 10N = 6(D - 5)
➠ 10N = 6D - 30
➠ N = (6D - 30)/10 -(eq.1)
2nd case:-
- Numerator + 5 & Denominator × 2 = fraction : 2/5
ATQ:-
➠ (N + 8)/2D = 2/5
➠ 4D = 5(N + 8)
➠ 4D = 5N + 40
- From eq.1 :-
➠ 4D = 5[(6D - 30)/10] + 40
➠ 4D = (6D - 30)/2 + 40
➠ 4D = (6D - 30 + 80)/2
➠ 4D = (6D + 50)/2
➠ 8D = 6D + 50
➠ 8D - 6D = 50
➠ 2D = 50
➠ D = 50/2
➠ D = 25
◗Denominator = 25
- Putting value in (eq.1):-
➩ N = [6(25) - 30] /10
➩ N = (150 - 30)/10
➩ N = 120/10
➩ N = 12
◗ Numerator = 12
Fraction:-
⇒ Fraction = N/D
⇒ Fraction = 12/25
Answer:-
Let , the fraction be x/y.
given that,
If the numerator is multiplied by 2 and the denominator is reduced by 5 we get 6/5.
According to the above situation,
After cross multiplication we get,
5(2x) = 6(y - 5)
10x = 6y - 30
And also given that,
If the numerator is increased by 8 and denominator is doubled we get 2/5.
According to this situation,
After cross multiplication we get,
Substitute "y" value in equation (1)
Hence, the fraction (x/y) is 12/25.