Question

In a given parallelogram PQRS,STis altitude to the base PQ.the area of PQRS is 120 cm . If PQ=15 cm,PT=6 cm,find STand SP

Answer 1

In parallelogram PQRS
PQ is the base and ST is perpendicular bisector
therefore;; area of parallelogram= base×height
120 =15×height (ST)
120/15=ST
8=ST

By phythagoras theoram
(SP)^2=(PT)^2+(ST)^2
(SP)^2=(6)^2+(8)^2
(SP)^2=36+64
(SP)^2=100
(SP) = under root of 10
(SP) =10cm

Answer 2

area of parallelogram= base × height

= 120 = 15 × height (st) = 120/15

=st = 8