Question

In a given process on an ideal gas, dW = 0 and dQ0. Then for the gas
(A) The temperature decreases
(B) The volume increases
(C) The pressure remains constant
(D) The temperature increases​

Answer 1

Answer:

C.The pressure remain constant

Explanation:

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Answer 2

Answer:

The temperature decreases

Explanation:

From first law of thermodynamics,

dQ=dU+dW

we have dQ=dU (asdW=0)

But dQ<0

∴dU<0

NC

V

ΔT<0

or ΔT<0

Hence, the temperature will decrease.