Question

in a given progessive wave y=5 sin (100(pi)t -0.4 (pi) x where x and y are in m meters and t in seconds what is the a )amplitude b) wave length c) frequency d)wave velocity e)particle velocity amplitude ( please show full process)​

Answer 1

Answer:

The given equation is y=5sin(100πt−0.4πx)

Compart is with the standard form of eqn. of progressive wave :y=rsin[2πtT−2πλx]

(a) amplitude, r=5m (b) 2πλ=0.4π,λ=2π0.4π=5m

(c) 2πT=100π,1T=v=100π2π=50Hz (d) wave velocity, υ=vλ=50×5=250m/s

(e) particle velocity, dydt=5×100πcos(100πt−0.4πx)

(dydt)max=500π×1m/s=500πm/s

Explanation:

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