Question

In a given reaction, 9 g of Al will react with
2A1 +3/2 02, → Al2o3
(1) 6 g 02
(2) 8 g 02
(3) 9 g 02
(4) 4 g 02​

Answer 1

$\huge\bigstar\underline\pink{ANSWER}$

the given equation is,

2Al + 3/2O2 → Al2O3

here, 2 mole of Aluminium reacts with 3/2mole of oxygen molecule

so, 1 mole of Aluminium will reacts with

13/2 ÷2 = 13/4mole of oxygen

atomic weight of aluminium is 27g

13/4mole of oxygen =( 3/4) × 32 = 24g

hence,

27g aluminium reacts with 24g O2

9g aluminium will reacts with

(24/27 ) × 9 =8 g of O2

your answer is option (2) 8g of O2

:)

Answer 2

Answer:

8g of O2

Explanation:

2moles of Al reacts with 3/2 moles of O2  

                                                                                                       1mole of Al = 27g hence,

2moles of Al= 2×27= 54g                                                                                                                                                                1mole of O2 = 32ghence,

3/2 mole of O2 = 48g

so....as per question....54g of Al reacts with 48g of O2so ..

9g of Al will react with 48×9/54 which is 8g

...so ...

9g of Al reacts   with      8g of O2

...hope it helps you......:).....

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