Question

in a given rhombus ABCD , angle CBD=59 find angle ACB DAB ADB ​

Answer 1

Answer:

Step-by-step explanation:

(i) ∠CBD=59

∠BOC=90° {diagnolsof rhombus bisect each other at right angles}

In Δ BOC

∠COB+∠OBC+∠BCO=180  {Angle sum propertyof a Δ}

90+59+∠bco=180

149+∠bco=180

∠bco=180-149

∠bco=31

(iii) ∠dbc=∠adb=59 {alternate interior angles are equal}

(ii) ∠dba=∠dbc=59 {diagnols of rhombus  bisect the angles}

in Δ dab

∠dab+∠abd+∠bda=180

∠dab+59+59=180

∠dab+118=180

∠dab=180-118

∠dab=62

PLS MARK ME THE BRAINLIEST IF YOU LIKED THE EXPLANATION

AND THE ANSWERS WERE CORRECT