Question

In a given sample of, 9g hydrogen and 46g nitrogen are present. In another sample, 5g hydrogen is present along with nitrogen. Calculate the amount of nitrogen in the second sample​

Answer 1

Answer:

0.978 g

Explanation:

Let amount of nitrogen be x

Due to law of constant proportion,

Mass of Hydrogen in Sample 1         Mass of Hydrogen in Sample 2

---------------------------------------------- = -------------------------------------------------------------

Mass of Nitrogen in Sample 1          Mass of Nitrogen in Sample 2

⇒9/46=x/5

⇒9/46×5=x

⇒x=0.978 g                                                                     (Approx.)

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