Question

In a given sample of ammonia, 9 g hydrogen and 42 g nitrogen
are present. In another sample, 5 g hydrogen is present
along with nitrogen. Calculate the amount of nitrogen in the
second sample​

Answer 1

Answer:

First sample:

9g of hydrogen and 42g of nitrogen are present. According to the law of definite proportion, hydrogen and nitrogen are present in the ratio of 9:42 i.e., 3:14

Second sample:

It is given that 5g of hydrogen is present along with nitrogen.

According to the law of constant proportion the second sample

must also contain hydrogen and nitrogen in 3:14 ratio.

⇒  $\frac{amount of hydrogen}{amount of nitrogen}$     = ratio

⇒$\frac{5}{amount of nitrogen}$  =  $\frac{3}{14}$

⇒ 14 × 5 = 3 × amt. of nitrogen

⇒ Amount of nitrogen = 70/3

⇒ Amount of nitrogen = 23.3g

Thus, the amount of nitrogen in the second sample is 23.3g.