Chemistry, asked by geniusgirl90, 2 months ago

In a given sample of ammonia, 9g hydrogen and 42g nitrogen are present. In another sample, 5g hydrogen is present along with nitrogen. Calculate the amount of nitrogen in the second sample​

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Answered by gayathrisaravanan96
6

Answer:

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In the first sample :

9g of hydrogen and 42g of nitrogen are present. According to the law of definite proportion,hydrogen and nitrogen are present in the ratio of 9:42 i.e.,3:14.

In the second sample :

It is given 5g of hydrogen is present along with nitrogen.

According to the law of constant proportion the second sample must also contain hydrogen and nitrogen in 3:14 ratio.

Amount of hydrogen

____________________. = Ratio

Amount of nitrogen

5

____________________. = 3/14

Amount of nitrogen

→14 × 5 = 3 × amt. of nitrogen

→Amount of nitrogen = 70/3

→Amount of nitrogen = 23.3g

Thus,the amount nitrogen in the second sample is 23.3g.

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Answered by santhalingam2005
2
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