In a given sample of ammonia, 9g hydrogen and 42g nitrogen are present. In another sample, 5g hydrogen is present along with nitrogen. Calculate the amount of nitrogen in the second sample
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In the first sample :
9g of hydrogen and 42g of nitrogen are present. According to the law of definite proportion,hydrogen and nitrogen are present in the ratio of 9:42 i.e.,3:14.
In the second sample :
It is given 5g of hydrogen is present along with nitrogen.
According to the law of constant proportion the second sample must also contain hydrogen and nitrogen in 3:14 ratio.
Amount of hydrogen
____________________. = Ratio
Amount of nitrogen
5
→____________________. = 3/14
Amount of nitrogen
→14 × 5 = 3 × amt. of nitrogen
→Amount of nitrogen = 70/3
→Amount of nitrogen = 23.3g
Thus,the amount nitrogen in the second sample is 23.3g.
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