Question

In a given sample of NH3 , 9g of hydrogen and 42g of nitrogen are present . In another sample of ammonia 5g of hydrogen is present along with nitrogen . Calculate the amount of nitrogen present in the second sample​

Answer 1

Answer:

• In the first sample:

9g of hydrogen and 42g of nitrogen are present.

According to the law of definite proportion, hydrogen and nitrogen are present in the ratio of 9:42 i.e., 3:14

• In the second sample:

 5g of hydrogen is present along with nitrogen.

According to the law of constant proportion the second sample  must also contain hydrogen and nitrogen in 3:14 ratio.

⇒  Amount of hydrogen/Amount of nitrogen = Ratio

⇒ 5/amount of nitrogen = 3/14

So,

14 × 5 = 3 × amt. of nitrogen

Amount of nitrogen = 70/3

Amount of nitrogen = 23.3g

Thus, the amount of nitrogen in the second sample is 23.3g.

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Explanation:

Answer 2

Answer:

In the first sample:

9g of hydrogen and 42g of nitrogen are present.

According to the law of definite proportion, hydrogen and nitrogen are present in the ratio of 9:42 i.e., 3:14

In the second sample:

 5g of hydrogen is present along with nitrogen.

According to the law of constant proportion the second sample  must also contain hydrogen and nitrogen in 3:14 ratio.

⇒  Amount of hydrogen/Amount of nitrogen = Ratio

⇒ 5/amount of nitrogen = 3/14

So,

14 × 5 = 3 × amt. of nitrogen

Amount of nitrogen = 70/3

Amount of nitrogen = 23.3g

Thus, the amount of nitrogen in the second sample is 23.3g.

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