In a given square ABCD, if the area of triangle ABD is 36cm², find (i) the area of triangle BCD; (ii) the area of the square ABCD
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Answer:
the area of triangle BCD = 36 cm²
area of the square ABCD = 72 cm²
Step-by-step explanation:
ABCD is a Square
=> AB = BC = CD = DA = X (Let say)
& ∠A = ∠B = ∠C = ∠D = 90°
area of triangle ABD = (1/2) * AB * AD
= (1/2) * X * X
= X²/2
area of triangle ABD is 36cm²,
=> X²/2 = 36
=> X² = 72
=> X = 6√2 cm
the area of triangle BCD = (1/2) * BC * CD
= (1/2) * X * X
= X²/2
= 36 cm²
the area of triangle BCD = 36 cm²
area of the square ABCD = AB * BC = X² = 72 cm²
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