Question

In a given system of unit standard measurement of mass is 100 gm,
standard measurements of length is 200 cm and standard mesurement
of time is 5 sec. 10J energy in the given system of unit has value N.
then value of N is?​

Answer 1

Answer:

hello

Explanation:

Answer :

0625

Solution :

[E]=mL2T−2

K2=K1[m1m2]a[L1L2]b[T1T2]c

=10[1kg100gm]1[1m200cm]2[1sec5sec]2

=10[1000gm100gm][100cm200cm]2[5]2

=10×10×14×25=625

brainliest please

Answer 2

So the unit of mass in new system is,

$\longrightarrow\sf{1\ M=100\ g}$

$\longrightarrow\sf{1\ M=0.1\ kg}$

And the unit of length in new system is,

$\longrightarrow\sf{1\ L=200\ cm}$

$\longrightarrow\sf{1\ L=2\ m}$

And the unit of time in new system is,

$\longrightarrow\sf{1\ T=5\ s}$

Dimension of energy is,

$\longrightarrow\sf{[E]=M\,L^2\,T^{-2}}$

So the unit of energy in new system is,

$\longrightarrow\sf{1\ E=1\ M\,L^2\,T^{-2}}$

Performing substitution for each values,

$\longrightarrow\sf{1\ E=1\ (0.1\ kg)\,(2\ m)^2\,(5\ s)^{-2}}$

$\longrightarrow\sf{1\ E=0.1\times2^2\times5^{-2}\times1\ kg\,m^2\,s^{-2}}$

Since $\sf{1\ kg\,m^2\,s^{-2}=1\ J,}$

$\longrightarrow\sf{1\ E=\dfrac{2}{125}\ J}$

$\longrightarrow\sf{1\ J=62.5\ E}$

$\longrightarrow\sf{10\ J=625\ E\quad\quad\dots(1)}$

But in the question,

$\longrightarrow\sf{10\ J=N\ E\quad\quad\dots(2)}$

Comparing (1) and (2), we get,

$\longrightarrow\underline{\underline{\sf{N=625}}}$

Hence 625 is the answer.