In a GP,2nd term is 6 and 5th term is 48,find 10th term
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Answer:
a10= 118
Step-by-step explanation:
a2 =6, a5=48
a+d = 6—————> 1
a+4d =48————> 2
2 - 1
3d = 42
d= 42/3
d=14
Put value of d in equation 1
a+14 = 6
a=6-14
a= -8
a10=a+9d
= -8+9x 14
= -8 +126
= 118
The 10th term of the ap is 118
anivarshraj:
it is gp bro
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