Question

in a GP ferst term is '1'
and 4th term is 27 then the
common vation of the same.​

Answer 1

Answer:

3

Step-by-step explanation:

Tn = ar^(n-1)

where a = 1st term = 1

Tn = value of the nth term = 27

n = term number = 4

r = common ratio = ?

Tn = ar^(n-1)

=> 27 = 1 * r^( 4-1 )

=> 27 = r ^ 3

=> 3^3 = r^3

=> r = 3