Question

In a GP if T3 = 18 and T6 = 486, find T10

Answer 1

Answer:

39366

Step-by-step explanation:

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In GP,

Tn = $ar^{n-1}$

T3 = ar² = 18

T6 = $ar^{5}$ = 486

By dividing T6/T3, we get,

r³ = 27

=> r = 3

Now, by substituing r=3 in T3, we get

a(3)² = 18

a = 2

Now,

T10 = $ar^{9}$ = $(2)(3)^{9}$ = 39366