Question

In a GP if T3 = 18 and T6 = 486 Find T10

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

39366

Step-by-step explanation:

Let us assume that the G.P. has first term= a and Common ratio = r.

Hence, the third  term, T₃= ar²

and the sixth term, T₆ = ar⁵

Given that, T₃= ar²= 18...... (1)

And T₆ = ar⁵ = 486 ..... (2)

Noe, dividing equation (2) with equation (1), we get,

r³ =27, ⇒ r= 3.

Hence, from equation (1), a(3²) =18, ⇒ a= 2.

We have to find the tenth term, T₁₀, which is = ar⁹= 2(3)⁹ =39366 (Answer).