Question

In a gp if the four terms is 2/3 and the 7th term is 16/81, then what is the first term of the series

Answer 1

Answer:

Step-by-step explanation:

ar^3=2/3 (1)and ar6=16/81(2)

divide both them  

r^3=8/27  

put r^3 in eq first (1)

then get a (8/27)=2/3

finally get a=9/4

The first term of the geometric series is 9/4