Question

In a GP the 3rd term is 24 and 6th term is 192. Find the 10th term. ​

Answer 1

Answer:

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Answer 2

Explanation:

we know that an = ar^n-1.

Given that 3rd term is 24

a3 = ar^2 = 24   ---- (1)

Given that 6th term is 192

a6 = ar^5 = 192   --- (2)

On dividing (2) by (1), we get

r^3 = 8

r = 2   --- (3).

Substitute (3) in (1), we get

a * (2)^2 = 24

4a = 24

a = 6.

The 10 th term a10 = 6 * (2)^9

                                = 3072.

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