Question

In a GP the 3rd term is 24 and 6th term is 192. Find the 10th term.

Answer 1

Ans.
3rd term of gp=a(r)³=24
6th term of gp=a(r)6=192
By dividing
r6-3=8
Therefore r=2
ar³=24
a=24/8
a=3
10th term of gp=ar9=3×(2³)³
=1536

Answer 2

HEYA!!!!

Here is your answer :
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$a3 = a {r}^{2} = 24 - - (1) \\ \\ a6 = a {r}^{5} = 195 - - (2) \\ \\ \\ dividing \: (2) \: by \: (1) \: we \: get \: \frac{ {ar}^{5} }{ {ar}^{2} } = \frac{195}{24} \\ \\ = > {r}^{3} = 8 = {2}^{3} \\ \\ r = 2 \\ \\ substituting \: r \: in \: (1) \: we \: get \: a = 6 \\ \\ therefore \: a10 = {ar}^{9} = 6 {(2)}^{2} = 3072$

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