Question

in a GP the third term is 24 and 6th term is 192 find the 10th term

Answer 1

Answer:

Step-by-step explanation:

a+2d=24......(1

a+5d=192.....(2

subtract--

-3d   =  -168

3d   =  168

d  =   56

put the value of "d" in (1)

a+2(56) = 24

a+ 112 =24

a = -88

so, 10th term =a+9d

putting value of a & d

-88+9×56  = 416

hence 10th term = 416

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