Question

In a graph of (6m and 4w) a committee of 4 person is to be selected .in how many way it can be done so that at least 1 man selected in comittee.

who solve first I mark him/her Brainly .
but no Google

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Answer 1

Answer:

209

Step-by-step explanation:

Given

Group is in form( 6m and 4w)

and number of selection is = 4

so

6C1 *4C3 + 6C2*4C2 + 6C34C1 + 6C4*4C0

= 6*4 + 6*5*4*3/2*2 + 6*5*4*4/6 + 6*5/2

= 24+90+80+15

=209

in above too solutions attached .....

Answer 2

Answer:

Given:

In a graph of (6m and 4w) a committee of 4 person is to be selected .in how many way it can be done so that at least 1 man selected in comittee.

Calculations:

1. 6m and 4w => Group
2. 4 => number of selection

=> 6C1 × 4C3 + 6C2 × 4C2 + 6C34C1 + 6C4 × 4C0

=> 6 × 4 + 6 × 5 × 4 × 3 / 2 × 2 + 6 × 5 × 4 × 4 / 6 + => 6 × 5 / 2

=> 24 + 90 + 80 + 15

=> 209