Question

In a grating spectrum, which spectral line in fifth order will overlap with the fourth order line

of 5461 Å
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Answer 1

Answer:

4368.8 angstroms

Explanation:

n*wavelength=constant

Answer 2

Given:

spectral line in fifth order will overlap with the fourth order line  of 5461 Å

According to the question we have :

$n_{1}=5 \quad \lambda_{1}=?$

$n_{2}=4 \quad \lambda_{2}=5461^{\circ} \mathrm{A}$

Now we get

$n_{1} \lambda_{1}=n_{2} \lambda_{2}$

$5 \times \lambda_{1}=4 \times 5461$

$\lambda_{1}=\frac{21844}{5}$

$\lambda_{1}=4368.8^{\circ} \mathrm{A}$

Hence the answer is 4368.8°A

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