in a group of 140 children, 66 of th like to eat apple and 97 of them like to eat mango. How many like both, if each of the children likes to eat atleast one of the fruits
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23
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Answers
Answer:
23
Step-by-step explanation:
WHY???
97+66=163 so,then subtract total no.of students 'from' what we added
=163-140=23
:. 23 students like both apple and mango.
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Concept:
The way that sets are represented by a person is always the same: as a group of clearly defined objects or elements. A capital letter designates a set.
The cardinal number of a set is the number of elements or members in that set. if A is a finite set and contains N members. So N is set A's cardinal number.
Note that an empty set's cardinal number is always zero.
For instance, set A has the following values: 1, 3, 6, 9, 10, 12, 18, and its cardinal number is 7. Thus, n(A) = 7.
Finding the total number of elements in any collection is the only formula for counting numbers.
n(A∪B) = n(A) +n(B) -n(A∩B)
n(A∪B∪C) = n(A) +n(B) +n(C)-n(A∩B) -n(C∩B) -n(A∩C) + n(A∩B∩C)
Given:
In a group of 140 children, 66 of th like to eat apple and 97 of them like to eat mango.
Find:
How many like both, if each of the children likes to eat atleast one of the fruits
Solution:
n(A)=66
n(B)=97
n(A∪B) = 140
We know that, n(A∪B) = n(A) +n(B) -n(A∩B)
⇒n(A∩B) = n(A) +n(B) -n(A∪B)
= 33+97-140
= 163 - 140
=23
Therefore. 23 students like both apple and mango.
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