Question

in a group of 15,7 can speak Hindi
, 8 can speak English and 3 can sperk neither what fraction of thr group can speak both hindi qnd English ​

Answer 1

Answer:

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Step-by-step explanation:

n(H)=10 {people who speak hindi}

n(E)=8 {People who speak English}

n(E∪H)=15 (total)

n(E∩H)=10+8–15=3 (Speaking both)

People who speak hindi only =10–3=7

Total ways of selecting 2 people =15C

2

=105

Favourable ways =7C

1

×3C

1

=21

Probability of occurrence =

105

21

=

5

1