Question

in a group of 20 boys and 10 girls ,5 boys and 3girls are honest If two person are selected at random from the group ,find the probability that either both are girls of both are honest.

Answer 1

2/35 is the answer
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Answer 2

Hence the probability that either both are girls of both are honest is 1/2

Step-by-step explanation:

Given:

Here in a group of 20 boys and 10 girls, 5 boys and 3 girls are honest.

Let total boys and girls = R

                                        =20 + 10

                                        = 30

Therefore favourable outcomes will be,  

say number of girls= m =10 girls

number of honest boys=n =5 boys

So therefore, m+n= 10+5 = 15

Hence Probability = $\frac{m+n}{R}$

                               =$\frac{15}{30}$

                               =$\frac{1}{2}$

Hence the probability that either both are girls of both are honest is $\frac{1}{2}$.