In a group of 24 cricket players 14 are batsman 10 bowlers 6 batsman and 2 bowlers are from mumbai . if a player is chose at random . what is the probability of choosing a bats man or player from mumbai
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Total number of samples, n(s)=24
Number of batsmen in the team, n(A)= 14
Number of players from Mumbai, n(B)=8
It is given that we have to see the selected player is a batsman or a player from Mumbai, so we have to use non-mutually exclusive addition theorem:
For that, we need n(AnB), which will be 6 because there are 6 batsmen from Mumbai and we need probability for selecting a batsman or player from Mumbai.
P(AuB)= P(A) + P(B) - P(AnB)
= 14/24 + 8/24 - 6/24
= 22/24 - 6/24
= 16/24
So the probability of choosing a batsman or a player from Mumbai is 16/24.
Step-by-step explanation:
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