In a group of 39 pupils, 10 play the flute only.
1 plays the piano only.
13 play neither instrument.
A student is selected at random.
What is the probability the student plays both instruments?
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Answer:
The total number of students who play at least one instrument is 10 + 12 + 6 =
28. The means there are 32 - 28 = 4 students who play neither of the
instruments. Therefore, the probability that a student plays neither instrument
is 4/32 = 1/8 = 0.125 = 12.5%.
Step-by-step explanation:
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