Question

In a group of 5 boys and 4 girls, three children are to be selected. In how
many different ways can they be selected such that at least one boy
should be there?​

Answer 1

Answer:

three children are to be selected are 2 boys. and 1 girl

Step-by-step explanation:

because then tere were equal no. if children 3boys and 3 girls

Answer 2

Answer:

The number of ways they can be selected is 79

Given :

There are 5boys and 4girls

3 children are to be selected

To find :

No. of ways they can be selected such that at least one boy should be there

Solution :

We may have (1 boy and 2 girls)or (2 boys and 1 girl) or (3 boys and 0 girl)

Therefore the Required number of ways

= (5C1 x 4C2) + (5C2 x 4C1) + (5C3)

= (5C1 x 4C1) + (5C2 x 4C2) + (5C3 x 4C1) + (5C2)

= (5 x 4) + ( 5 x 4 x 3 / 2 × 1 ) + (5 x 4 x 4) /(3×1) + 5/ 2

= 20 + 30 + 26.66 + 2.5

= 79.16

approx 79

Hence , the number of ways they can be selected is 79.

#SPJ2