Question

In a group of 5 families, every family has a certain number of children, such that the number of children forms an arithmetic progression with a common difference of one, starting with two children in the first family. Despite the objection of their parents every child in a family has three times as many pets to look after as the number of offspring in the family. What is the total number of pets in the entire group of five families. Tcs

Answer 1

Answer: 270

Step-by-step explanation: The number of children in a family are in AP having first term a =2 and common difference d=1

AP is 2,3,4,5,6

Number of pets are three times as many as number of offspring in a family

If the number of offspring in a family are n then number of pets in each  child will be 3×n

Therefore number of pets in each family will be $3 n^2$

Total number of pets will be (respectively).

=3( 4+9+16+25+36)

=3(90) =270  

Therefore total number of pets in the entire group is 270