Question

In a group of 50 items each one is either type A or type B and is either sweet or hot. 14 are sweet items of type A, 31 are type B and 18 are hot. The number of hot items of type B is​

Answer 1

Step-by-step explanation:

O 31 -18

it gives

17 this is the Ans

O 31+18= 49 .

which is correct friend I do t know haa if one of these is correct then write it down if not then don't mind cause I am week in maths and it to I try to solve maths

Answer 2

Step-by-step explanation:

Given In a group of 50 items each one is either type A or type B and is either sweet or hot. 14 are sweet items of type A, 31 are type B and 18 are hot. The number of hot items of type B is

• So there are 50 items.
• So the number of type B items is 31
• So type A = total – type B
•                 = 50 – 31
•           So type A = 19 items
• Now the hot items of type A = type A – sweet items of type A
•                                                = 19 – 14
•                                                = 5
• Now the total hot items are 18.
• Therefore the hot items of type B will be 18 – 5 = 13

Reference link will be

https://brainly.in/question/11772665