in a group of , 50 persons play basketball 20 play football and find the persons play at least one of the two games
Answers
Explanation:
In a school of 50, 35 play football and 25 play hockey. If 10 students do not play any of these two games then how many students play both football and hockey?
The question is incorrect. I assume that the required answer is the number of people playing football and hockey
There are 4 groups of people:
The ones who play only football
The ones who play only hockey
The ones who play both (let us assume this to be x)
The ones who play none (We are told this is 10)
Now, we know the total number of people is 50
Therefore, the number of people who play at least one sport is 50 less the number of people who play NO SPORT
ie. 50-10= 40
Now, we know that
the number of people who play Hockey is 25
the number of people who play Football is 35
Adding up these two numbers gives us 40 plus the number of people who play both sport (Since the overlap zone is being considered twice)
Thus,
35+25=40+x
=> x= 20
Therefore
No. of people playing only football: 35-x= 35-20= 15
No. of people playing only hockey: 25-x= 25-20= 5
No. of people playing both: 20
No. of people playing none: 10
Simple!
Note; This is best solved using a Venn Diagram, that makes it very clear. I'll upload one if I can find it
Explanation:
50 play basketball, 20 play football, and 10 play at least both. How many plays at least one of the two games? Last updated April 12. ·