Math, asked by rohithsaishankar, 5 months ago


In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boj
should be there?​

Answers

Answered by varun4375
3

Answer:

Number of ways to select a group with no boys (i.e., all girls) is 6C0 x 4C4 = 1 x 1 = 1. Thus, the number of was to select a group with at least 1 boy is 210 - 1 = 209. Bunuel wrote: QZ wrote: In a group of 6 boys and 4 girls, four children are to be selected

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