In a group of 8 boys and 4 girls, four children are to be selected. in how many different ways can they be selected such that at least one boy should be there?
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given 8 Boys and 4 girls
children to be selected 4 (condition:Atleast one boy should be selected, that means we can choose 1 boy and 3 girls or 2 boys or 2 girls or 3 boys and 1 girl or 4 boys and no girl)
so, 8C1 x 4C3 + 8C2 x 4C2 +8C3 x 4C1 + 8C4 x 4C0 =
calculate the answer
children to be selected 4 (condition:Atleast one boy should be selected, that means we can choose 1 boy and 3 girls or 2 boys or 2 girls or 3 boys and 1 girl or 4 boys and no girl)
so, 8C1 x 4C3 + 8C2 x 4C2 +8C3 x 4C1 + 8C4 x 4C0 =
calculate the answer
Jezriel:
494
✌great
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