In a group of 80 employees, the number of employees who are engineers is twice that of the employees who are MBAs. The number
of employees who are not engineers is 32 and that of those who are not MBAs is 56. The number of employees who are both
engineers and MBAs is twice that of the employees who only MBAs are. How many employees are neither engineer (B.tech) no's
MBAs?
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Given In a group of 80 employees, the number of employees who are engineers is twice that of the employees who are MBAs. The number of employees who are not engineers is 32 and that of those who are not MBAs is 56. The number of employees who are both engineers and MBAs is twice that of the employees who only MBAs are. How many employees are neither engineer (B.tech) nor MBAs?
- So group of employees = 80
- So let Engineers = E and MBA be M
- According to the question
- E = 2M
- The employees who are not engineers is 32
- So 80 – 2M = 32
- Or 2M = 48
- Or M = 24
- So let employees who are both engineers and MBA = E1
- So E1 = 2 (M – E1)
- = 2(24 – E1)
- E1 = 48 – 2E1
- 3E1 = 48
- Or E1 = 48 / 3
- Or E1 = 16
- Now total = M + E + E1 + x (let x be no one)
- 80 = 24 + 48 – 16 + x
- 80 = 56 + x
- So x = 80 – 56
- Or x = 24
- Therefore neither engineer nor MBA are 24
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