Question

in a group of athlete am in a school 21 are the basketball team, 26 in the hockey team and 29 in the football team if 14 play hockey and basketball 12 play football and basketball 15 play hockey and football and 8 play all three games find first how many players are there in all second how many play football only of sets​

Answer 1

Answer:

Let B, H, F denote the sets of members who are in the basket hall team, hockey team and football team respectively. 

Given n(B)=21,n(H)=26,n(F)=29. n(H∩B)=14,n(H∩F)=15, n(F∩B)=12 and n(B∩H∩F)=8.

We have to find n(B∪H∪F).

n(B∪H∪F)=n(B)+n(H)n(F) −n(B∩H)−n(H∩F)−n(F∩B)+n(B∩H∩F).

n(B∪H∪F)=(21+26+29)−(14+15+12)+8=43

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