Question

in a group of cows and cocks. The number of legs is 14 more than twice of their number of heads . find the total number of cows and cocks.​

Answer 1

Answer:

Let there be x cows and y hens A cow has 4 legs and a hen has 2 legs

⇒4x+2y=2(x+y)+14

⇒4x−2x+2y−2y=14

⇒2x=14

⇒x=7

Answer 2

Step-by-step explanation:

Let no. of cosws =x & no. of chickens =y

∴ total no. of heads =x+y

& Total no. of legs =4×xf2×y

=4x+2y

Now, given that no. of legs is 14 more than twice no of heads.

∴2(x+y)+14=4x+2y

∴2x+2y+14=4x+2y −(1)

∴14=2x

∴x=7⇒ No. of cows.