In a group of cows and hens, the number of legs are 14 more than twice the number of heads. The number of cows is
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let
Cow=x
& Hen=y
total number of Cow & Hens or heads=x+y
the number of legs(cow +hens) or 4x+2y=2(x+y)+14
4x+2y=2x+2y+14
solve
2x=14
x=7
numer of cows are 7
Cow=x
& Hen=y
total number of Cow & Hens or heads=x+y
the number of legs(cow +hens) or 4x+2y=2(x+y)+14
4x+2y=2x+2y+14
solve
2x=14
x=7
numer of cows are 7
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