In a group of cows and hens the number of legs is 14 more than twice the number of heads.The number of cows is
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105
Let the no of cow=y,no of legs=4y
No of hems=z,no of legs=2z
As the question,4x+2y=2(x+y)+14
4x+2y=2x+2y+14
4x=2x+14
4x-2x=14
x=14/2=7
So,no of cows=7
No of hems=z,no of legs=2z
As the question,4x+2y=2(x+y)+14
4x+2y=2x+2y+14
4x=2x+14
4x-2x=14
x=14/2=7
So,no of cows=7
av420p59f8o:
Thanq soo much
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7
Answer:
ANSWER
Let there be x cows and y hens. A cow has 4 legs and a hen has 2 legs.
⇒4x+2y=2(x+y)+14
⇒x=7
Step-by-step explanation:
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