In a group peacocks and deer having 260 legs and 100 heads find out how many peacocks and deers
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Step-by-step explanation:
let the no. of peacocks be x
let the no. of deer be y
ATQ..
2x+4y=260 ......equation 1
ATQ..
x+y= 100...... equation 2
multiply equation 2 by 2
2x+2y=200..... equation3
sub. equation 3 from 1
2x+4y=260
-2x-2y= -200
____________
0+2y= 60
y=60÷2
y=30
put y =30 in equation 1
2x+4×30=260
2x+120=260
2x=260-120
2x=140
x=70
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