Question

in a group there are 21 children 35 ladies and 42 gents they all want to stay in same Hotel find the maximum number of rooms required to their stay so that equal number of members would stay in each room also with the condition that children female male stay in a separate room​

Answer 1

Answer:

14 rooms will be in hotel

Answer 2

Answer:

21 children

35 ladies

and 42 gents

condition is equal number of members would stay in each room

hence the numbers of members who stay at one room is divisible by 21,35 and 42. 7 is the number which divisible by 21,35 and 42

21/7=3

35/7=5

42/7=6

hence 3+5+6=14 rooms