In a group, there are 21 children, 35 ladies and 49 gents. They all want to stay in same hotels. Find the minimum number of rooms for their stay so that in each room, equal number of members stay. Also, with the condition that children, females and gents stay in separate rooms.
Answers
Step-by-step explanation:
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Step-by-step explanation:
Correct option is
A
441
Total number of girls in the group =4
Total number of boys in the group =7
Probability of selecting atleast one boy and one girl =?
By considering following ways we can select
i) 1 girls +4 boys ⇒
4
C
1
×
7
C
4
ii) 2 girls +3 boys ⇒
4
C
2
×
7
C
3
iii) 3 girls +2 boys ⇒
4
C
3
×
7
C
2
iv) 4 girls +1 boy ⇒
4
C
4
×
7
C
1
Total number of ways =(
4
C
1
×
7
C
4
)+(
4
C
2
×
7
C
3
)+(
4
C
3
×
7
C
2
)+(
4
C
4
×
7
C
1
)
=140+210+84+7
=441