Question

In a group there are 50 hens, 45 goats, 8 camels and some of their keepers. If the total number of feet exceeds the number of heads by 224 then find the number of keepers in the group?

Answer 1

Let the number of keepers be x
Then, no. of heads=50+45+8+x
no. of feet :-
Hens=50*2=100
Goats=45*4=180
Camels=8*4=32
Keepers=x*2=2x
so, total no. of feet=100+180+32+2x=312+2x
Total no. of feet exceeds heads by 224.
100+180+32+2x-(50+45+8+x) =224
100+180+32+2x-50-45-8-x =224
312+2x-103-x =224
209+x=224
x=15

No. of keeper=15
Answer is 15.....

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Answer 2

Hey buddy!!

Here is your answer!!

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Let the number of keepers be x.
Then total number of feet =2×50+4×45+4×8+2x
=2x+312

Total number of heads
= 50+45+8+x
=103+x
Now, (2x+312)=(103+x)+224
x=15
⚫️So the number of keepers in the group is 15.

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