Question

In a grouped frequency data, class intervals 1-20,21-40,41-60....., then the class width is

Answer 1

First make ti continuous

0.5 -20.5

20.5-40.5

40.5-60.5

class width=h=40.5-20.5=20

Answer 2

In a grouped frequency data, class intervals 1 - 20 , 21 - 40 , 41 - 60 . . . . . then the class width is 20

Given : In a grouped frequency data, class intervals 1 - 20 , 21 - 40 , 41 - 60 . . . . .

To find : The class width

Tip : Class Length or Class Size or Class Width of the class interval of any class is defined to be the difference between the lower and upper class boundaries ( not class limits) of that particular class interval.

Class Width = Upper Class boundary - Lower class boundary

Solution :

Step 1 of 3 :

Write down the given class intervals

In the grouped frequency data class intervals are given by 1 - 20 , 21 - 40 , 41 - 60 . . . . .

Step 2 of 3 :

Generate continuous class intervals

The given class intervals are such that the upper class limit of any class is not equal to lower class limit of successive class

So it is a discontinuous graphical representation of the data

We convert this to continuous graphical representation of the data so that the class intervals are 0.5 - 20.5 , 20.5 - 40.5 , 40.5 - 60.5 , . . . .

Step 3 of 3 :

Find class width

Hence the required class width

= Upper Class boundary - Lower class boundary

= 20.5 - 0.5

= 20

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